Fisica
Nuclear fusion is a reaction in which atomic nuclei merge to form the nucleus of a new atom. The mass of the new atom’s nucleus is lower than the sum of the merging nuclei’s masses, a difference that is released as energy. This is, for instance, the reaction that occurs in the Sun. The energy released during fusion can be calculated by the equation E = Δmc2, where Δm is the difference between the initial and final masses in the reaction, and c is the speed of light. When calculating the aforementioned energy, nucleus mass can be conveniently quantified using the atomic mass unit (u), which is roughly equivalent to 900 MeV (1 u 900 MeV). Consider the hypothetical nuclear fusion reaction 222X + 4Y 221Z. Note that the masses of 222X, 4Y, and 221Z are 222 u, 4 u, and 221 u, respectively. The amount of energy released in this reaction is
- A)5 MeV.
- B)450 MeV.
- C)900 MeV.
- D)4500 MeV.GABARITO
Explicação
# Análise da Questão de Fusão Nuclear ## Por que a alternativa **D) 4500 MeV** está correta: **Cálculo do defeito de massa:** - Massa inicial: 222 u + 4 u = 226 u - Massa final: 221 u - Δm = 226 - 221 = **5 u** **Conversão para energia:** - Usando 1 u ≈ 900 Me... Ver explicação completa e trilha adaptativa →